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For Ray (See related posts)

In response to his question here, assuming your content is in a string called $content:

$num_paras = substr_count($content, '
'); 
switch ($num_paras) {
  case 1:
    $image = 'one.jpg';
    break;
  case 2:
    $image = 'two.jpg';
    break;
  case 3:
    $image = 'three.jpg';
    break;
  default:
    $image = '';
    break;
}
to php ray by ubernostrum on Sat Oct 15 18:35:25 +0000 2005

Comments on this post

joeldg posts on Oct 16, 2005 at 04:09
another way
of course depending on image naming..
where 0.gif is a 1x1 pixel clear gif.
$image_name = substr_count($content, '
') . ".gif";


or if coming from a database (i.e. data filtered through strip tags)

$image_name = substr_count($content, '\n') . ".gif";

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