Convert numbers to words
Ugly code. But it works. If you have something better, then post it.
class Number def self.to_words(number) Number.new.to_s(number) end def self.commify(number) (s=number.to_s;x=s.length;s).rjust(x+(3-(x%3))).gsub(/(\d)(?=\d{3}+(\.\d*)?$)/,'\1,') end def initialize @unit = %w[zero one two three four five six seven eight nine] @teen = %w[ten eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteen] @tens = %w[zero ten twenty thirty fourty fifty sixty seventy eighty ninety] @qtys = %w[hundred thousand million billion trillion quadrillion quintillion] @zero = ["zero"] @hundred = "hundred" @sepr = "and" end def to_s(number) out = quantify(number).flatten for x in 0 .. out.length - 1 out[x] = nil if out[x] == @sepr && out[x+1] == @sepr end out.compact! out = @zero if out.length == 1 && out[0] == @sepr out.pop while out.last == @sepr out.shift while out.first == @sepr out.join(' ').gsub(/ ,/,',') end private def padded_groups(v) out = [] padded = (s=v.to_s;x=s.length;s).rjust(x+(3-(x%3))).gsub(//,'0') padded.scan(/.{3}/) end def wordify(v) out = [] zero = '0'[0] h, t, u = v[0] - zero, v[1] - zero, v[2] - zero if h != 0 out << @unit[h] out << @hundred end out << @sepr if h != 0 && (t != 0 || u != 0) out << @sepr if h == 0 && t == 0 && u != 0 if t == 1 out << @teen[u] else out << @tens[t] if t != 0 out << @unit[u] if u != 0 end return out end def quantify(v) v = padded_groups(v).reverse pos = v.length - 1 out = [] while pos >= 0 word = wordify(v[pos]) if word[0] != nil out << word out << @qtys[pos] if pos != 0 else out << @sepr end pos -= 1 end return out end end # for number in [ # 0, # 1, # 3, # 11, # 100, # 1000, # 1001, # 1100, # 1101, # 1_000_001, # 8_000_000_000, # 8_000_000_001, # 4_567_890_923, # 6_804_567_890_903, # 5_006_804_567_890_903 # ] # print "#{Number.commify(number)}: #{Number.to_words(number)}\n" # end